22x+2x^2=160

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Solution for 22x+2x^2=160 equation:


Simplifying
22x + 2x2 = 160

Solving
22x + 2x2 = 160

Solving for variable 'x'.

Reorder the terms:
-160 + 22x + 2x2 = 160 + -160

Combine like terms: 160 + -160 = 0
-160 + 22x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-80 + 11x + x2) = 0

Factor a trinomial.
2((-16 + -1x)(5 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-16 + -1x)' equal to zero and attempt to solve: Simplifying -16 + -1x = 0 Solving -16 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + -1x = 0 + 16 Combine like terms: -16 + 16 = 0 0 + -1x = 0 + 16 -1x = 0 + 16 Combine like terms: 0 + 16 = 16 -1x = 16 Divide each side by '-1'. x = -16 Simplifying x = -16

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {-16, 5}

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